Three consumers with resistance of 20, 40 and 24 Ohm are connected in parallel.

| May 25, 2021 | education

Three consumers with resistance of 20, 40 and 24 Ohm are connected in parallel. The voltage at the ends of this section of the circuit is 24 V. Determinant of the current strength in each consumer, the total current strength in the section of the circuit and the resistance of the section of the circuit.

Determine the total resistance of this circuit of three resistors r0:

1 / r0 = 1/20 + 1/40 + 1/24 = (2 + 1) / 40 + 1/24 = 3/40 + 1/24 = (18 + 10) / 240 = 28/240 (Ohm) … r0 = 240/28 = 8.57 Ohm is the total resistance of the circuit.

Determine the total current in the circuit i0: i0 = 24 V / (28/240) = 2.8 A.

Let’s determine the current in each circuit:

i1 = 24 V / 20 V = 1.2 A; i2 = 24 V / 40 V = 0.6 A; i3 = 24 V / 24 Ohm = 1 A.

Check: the total current is equal to the sum of the three currents,

i0 = i1 + i2 + i3 = 1.2 A + 0.6 A + 1 A = 2.8 A = 2.8 A. That is, the currents and total resistance are found correctly.

Answer: i0 = 2.8 a, r0 = 8.57 ohms.



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