Three corners of a quadrilateral inscribed in a circle, taken in the order of succession, are as 2: 6: 7

Three corners of a quadrilateral inscribed in a circle, taken in the order of succession, are as 2: 6: 7, find the corners of the quadrilateral.

Let AVSD be a quadrilateral inscribed in a circle,
<A: <B: <C = 2: 6: 7. Let’s take the part as x. I.e
<A = 2 * x; <B = 6 * x; <C = 7 * x.
As you know, in a quadrilateral inscribed in a circle, the sum of opposite angles is 180 °, that is, <A + <C = 180 °, <B + <D = 180 °.
<A + <C = 2 * x + 7 * x = 9 * x = 180 °. x = 180 ° / 9 = 20 °.
<A = 2 * x = 2 * 20 ° = 40 °;
<B = 6 * x = 6 * 20 ° = 120 °;
<C = 7 * x = 7 * 20 ° = 140 °;
<D = 180 ° – <B = 180 ° – 120 ° = 60 °.