Three forces act on the body along a straight line in one direction, F1 = 50H, F2 = 100H, F3 = 180H.

Three forces act on the body along a straight line in one direction, F1 = 50H, F2 = 100H, F3 = 180H. What is the resultant of these forces?

The task presents the most elementary case of the arrangement of forces: along one line, and in one direction. Let’s schematically depict this case:

—> F1 —> F2 —> F3.

This distribution of forces F1, F2, F3 in space gives the following formula for the resulting force Fp = F1 + F2 + F3.

Knowing that F1 = 50H; F2 = 100H; F3 = 180N, we get the value of the resultant force:

Fr = 50H + 100H + 180H = 330H.

Answer: Fр = 330Н.