Three identical bodies are completely immersed in one and the same liquid. The first is pewter, three times

Three identical bodies are completely immersed in one and the same liquid. The first is pewter, three times lead, the third is a body of wood. Which of them is affected by the least Archimedean force?

If the bodies have the same mass:

Given:

m1 = m2 = m3 = m – the mass of the bodies is the same;

ro1 = 7300 kg / m ^ 3 – tin density;

ro2 = 11300 kg / m ^ 3 – lead density;

ro3 = 450 kg / m ^ 3 – wood density;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the smallest Archimedean force.

Since all bodies are immersed in the same liquid (density ro), then:

A1 = ro * V1 * g = ro * m / ro1 * g = ro * m / 73000;

A2 = ro * V2 * g = ro * m / ro2 * g = ro * m / 113000;

A3 = ro * V3 * g = ro * m / ro3 * g = ro * m / 4500.

Since ro * m / 113000 <ro * m / 73000 <ro * m / 4500, the smallest Archimedean force acts on a body of lead.

If, according to the condition of the problem, the bodies have the same volume, then an equal Archimedean force acts on all bodies.