Three radii are drawn in a circle with center O: OA, OB, OC so that OB is perpendicular to AC
| January 12, 2021 | education
Three radii are drawn in a circle with center O: OA, OB, OC so that OB is perpendicular to AC and the segments OB and AC intersect. Prove that AB = BC.
Since, by condition, OB is perpendicular to AC, and point O belongs to AC, then OB is perpendicular to OA and OС, and then triangles AOB and COB are rectangular, in which OA = OB = OС = R.
Then the triangle AOB is equal to the triangle СOB along two legs, and then AB = BC, which was required to prove.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
