Three radii OB, OC, OA, AOB = BOC are drawn in a circle with center O. Prove that OAB = OCB
| November 28, 2020 | education
Given: OA, OB, OC – the radii of the circle O; ⦟AOB = ⦟BOC
Prove: ⦟OAB = ⦟OCB
Proof: OA, OB, OC – radii of circle O (by condition) →
OA = OB = OC (as radii of one circle)
⦟AOB = ⦟BOC (by condition) → ΔABO = ΔBCO (along 2 sides and the angle between them) → ⦟OAB = ⦟OCB (as corresponding elements in equal figures)
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