Three sides of the triangle are given a = 31, b = 40√2, c = 41. Find the corner opposite side c.

We apply, for the solution, the cosine theorem for triangles, from which we determine the unknown angle C.

AB ^ 2 = AC ^ 2 + BC ^ 2 – 2 * AC * BC * CosC.

1681 = 3200 + 961 – 2 * 40 * √2 * 31 * CosС.

2480 * √2 * CosС = 2480.

СosC = 1 / √2 = √2 / 2.

C = 45.

Answer: Angle C is 45.



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