Three tangents AB, AC and AD are drawn from one point A to two externally tangent circles
| March 10, 2021 | education
Three tangents AB, AC and AD are drawn from one point A to two externally tangent circles with centers at the points O and O1, and AC passes through the tangency point of the circles C. Prove that AB = AC = AD.
Since the tangent AC passes through the tangent point of the circles, this tangent is common to the circles.
By the property of tangents drawn from one point, the lengths of these tangents are equal, then AC = AB, and AD = AC, and therefore AB = AC = AD, which was required to prove.
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