Three test tubes without labels contain solutions of sulfate, nitrate and chloride acids

Three test tubes without labels contain solutions of sulfate, nitrate and chloride acids. how to determine, using only one reagent, which acid is in each of the tubes.

Let’s take copper as a reagent.

To understand what kind of reaction will occur when copper and sulfate acid are mixed, we will compose and solve the equation:

2H2SO4 + Cu = SO2 ↑ + CuSO4 + 2H2O,

So, in the course of the reaction, we get the release of sulfur dioxide, which, by smell, resembles a burnt match.

Now let’s compose the equation for the reaction of copper and nitrate acid:

Cu + 4HNO3 = Cu (NO3) 2 + 2NO2 + 2H2O

As a result, we get a violent release of brown gas, after which the solution will turn blue or green.

If you mix copper and chloride acid, there will be no reaction. They won’t interact.