Through 40 g of a solution with a mass fraction of sodium hydroxide of 6%, carbon dioxide was passed until sodium

Through 40 g of a solution with a mass fraction of sodium hydroxide of 6%, carbon dioxide was passed until sodium carbonate was formed. Calculate the volume of gas consumed in the reaction.

Given:
m solution (NaOH) = 40 g
ω (NaOH) = 6%

To find:
V (CO2) -?

Decision:
1) Write down the equation of a chemical reaction:
2NaOH + CO2 => Na2CO3 + H2O;
2) Calculate the molar mass of NaOH:
M (NaOH) = 40 g / mol;
3) Calculate the mass of NaOH:
m (NaOH) = ω (NaOH) * m solution (NaOH) / 100% = 6% * 40/100% = 2.4 g;
4) Calculate the amount of NaOH substance:
n (NaOH) = m (NaOH) / M (NaOH) = 2.4 / 40 = 0.06 mol;
5) Determine the amount of substance CO2:
n (CO2) = n (NaOH) / 2 = 0.06 / 2 = 0.03 mol;
6) Calculate the volume of CO2:
V (CO2) = n (CO2) * Vm = 0.03 * 22.4 = 0.672 l.

Answer: The volume of CO2 is 0.672 liters.