Through a coil with an inductance of 0.4 m H and an area of 10 cm2, a current of 0.5 A flows.

univerkov | December 12, 2020 | education

Through a coil with an inductance of 0.4 m H and an area of 10 cm2, a current of 0.5 A flows. What is the induction of the field inside the coil if it has 100 turns?

LI = nBS, we derive the magnetic field induction B = LI / nS, substitute the known values and get, 0.4 * 10 ^ -3 * 0.5 / 100 * 10 ^ -4 =
0.2 * 10 ^ -3 / 0.1 = 0.0002 / 0.1 = 0.002.
Answer: 0.002T

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