Through an excess of barium hydroxide solution, 230 moles of carbon dioxide were passed.

| September 16, 2021 | education

Through an excess of barium hydroxide solution, 230 moles of carbon dioxide were passed. Calculate the mass of the sediment.

Let us find the necessary mass of BaCO3 for the reaction to proceed by the number of moles and molar mass: m (BaCO3) = M (BaCO3) * n (BaCO3) = 197 g / mol * 1 mol = 197 g.

We write down the reaction equation, over the equation we write what we know from the condition. Below we write what is seen from the equation (the number of moles of CO2 = 1) and what was found in the first action (the required mass of BaCO3 for the reaction to proceed = 197 g):
230 mol X g
Ва (ОН) 2 + СО2 -> BaCO3 + H2O
n = 1 mol m = 197 g

We make the proportion:
230 mol (СО2) – Х g (ВаСО3)
1 mol (СО2) – 197 g (ВаСО3)

Calculate the mass of the sediment: m (BaCO3) = 230 * 197 = 45.3 kg
Answer: The mass of the BaCO3 sediment is 45.3 kg.



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