Through bromine water passed 0 2 mol of ethylene, what mass 1 2 methane dibromium

Through bromine water passed 0 2 mol of ethylene, what mass 1 2 methane dibromium is obtained as a result of the reaction.

Let’s implement the solution:
1. We compose the reaction equation:
C2H4 + Br2 = C2H4 (Br2) – addition reaction, 1.2 dibromoethane was obtained;
2. Let’s make calculations using the formulas:
M (C2H4) = 12 * 2 + 4 = 28 g / mol;
M (C2H4Br2) = 12 * 2 + 4 + 79.9 * 2 = 187.8 g / mol;
3. Let’s make the proportion according to the equation:
0.2 mol (C2H4) – X mol (C2H4Br2);
-1 mol -1 mol hence, X mol (C2H4Br2) = 0.2 * 1/1 = 0.2 mol;
4. Find the mass of 1,2 dibromoethane by the formula:
m (C2H4Br2) = Y * M = 0.2 * 187.8 = 37.56 g;
Answer: in the addition reaction, 1.2 dibromoethane with a mass of 37.56 g is formed.