Through point A, a tangent AB and a secant are drawn, intersecting the circle at points C

Through point A, a tangent AB and a secant are drawn, intersecting the circle at points C and K so that AC = 4cm, AK = 16cm. Find the length AB.

By the property of the tangent to the circle and the secant, coming out of one point, the square of the distance from this point to the point of tangency is equal to the product of the length of the secant by the length of its outer part.

AB ^ 2 = AK * AC.

AB = √AK * AC = √4 * 16 = √64 = 8 cm

Answer: AB = 8 cm.



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