Through the ends A and B of the circular arc with center O, tangents AB and BC

Through the ends A and B of the circular arc with center O, tangents AB and BC are drawn less than the arc AB is equal to 64 Find the angle ACB.

The central angle AOB rests on the arc AB, the degree measure of which, by condition, is 64, then the central angle AOB = 64.

The radii ОА and ОВ, drawn to the points of contact A and B, are perpendicular to the tangents АС and ВС, then in the quadrangle ОАСВ the angle АСВ = (360 – ОАС – ОВС – АВ) = (360 – 90 – 90 – 64) = 116.

Answer: The value of the angle ACB is equal to 116.



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