Through two pipes, 1/3 of the pool is filled in every hour; through the first pipe, one-tenth of the pool

Through two pipes, 1/3 of the pool is filled in every hour; through the first pipe, one-tenth of the pool is filled in an hour. What part of the pool will be filled in an hour through the second pipe.

According to the condition of the problem, 1/3 of the pool is filled through two pipes in 1 hour, and through the first 1/10 of the pool, therefore, in order to find which part of the pool will be filled with the second pipe, it is necessary to subtract the part from the filling with both pipes that the first fills pipe and get that

1/3 – 1/10 = we reduce to a common denominator 30, an additional factor to the first fraction is 10, and to the second – 3, we get = 10/30 – 3/30 = 7/30.

Therefore, through the second pipe, 7/30 of the pool is filled in 1 hour.

Answer: through the second pipe, 7/30 of the pool is filled in one hour.