To 10.4 barium chloride was added 9.8 g of sulfate acid. Determine the mass of the sediment.

We write down the equation of the process:
BaCl2 + H2SO4 = BaSO4 + 2HCl – ion exchange, a precipitate of barium sulfate was formed;

Calculations by formulas:
M (BaCl2) = 208.3 g / mol;

M (BaSO4) = 233.3 g / mol;

M (H2SO4) = 98 g / mol.

Let’s determine the amount of starting materials:
Y (BaCl2) = m / M = 10.4 / 208.3 = 0.05 mol (deficient substance);

Y (H2SO4) = m / M = 9.8 / 98 = 0.1 mol (substance in excess);

Y (BaSO4) = 0.05 mol since the amount of these substances is 1 mol.

Calculations are made for the substance in deficiency.

We find the mass of the sediment:
m (BaSO4) = Y * M = 0.05 * 233.3 = 11.67 g

Answer: the mass of barium sulfate is 11.67 g