To 100 g of 10% sodium hydroxide solution was added 100 g of 20% sulfuric acid. calculate the mass of salt

2NaOH + H2SO4 = Na2SO4 + 2H2O.
You need to find the mass of sodium sulfate.
1) Mass of sodium hydroxide solute: 100 * 10/100 = 10g.
2) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
3) Amount of sodium hydroxide substance: 10/40 = 0.25 mol.
4) Mass of sulfuric acid solute: 100 * 20/100 = 20g.
5) Molar mass of sulfuric acid: 1 * 2 + 32 + 16 * 4 = 98.
6) Amount of sulfuric acid substance: 20/98 = 0.20 mol.
Lack of sulfuric acid. The calculation is carried out on it.
7) The amount of sodium sulfate substance is 0.2 mol.
8) Mass of sodium sulfate: 0.2 * 142 = 28.4 g – answer.



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