To 100 g of a solution of hydrochloric acid with a mass fraction of 20% is added a solution of sodium
To 100 g of a solution of hydrochloric acid with a mass fraction of 20% is added a solution of sodium carbonate with a mass of 50 g with a mass fraction of 40% find the mass of the resulting gas
1. We write down the equation of the proceeding reaction:
2HCl + Na2CO3 = 2NaCl + H2O + CO2 ↑;
2.Calculate the mass of the acid:
m (HCl) = w (HCl) * m (solution) = 0.2 * 100 = 20 g;
3. find the chemical amount of hydrogen chloride:
n (HCl) = m (HCl): M (HCl) = 20: 36.5 = 0.5479 mol;
4.Calculate the mass of sodium carbonate:
m (Na2CO3) = w (Na2CO3) * m (solution) = 0.4 * 50 = 20 g;
5.determine the amount of carbonate:
n (Na2CO3) = m (Na2CO3): M (Na2CO3);
M (Na2CO3) = 2 * 23 + 12 + 3 * 16 = 106 g / mol;
n (Na2CO3) = 20: 106 = 0.1887 mol;
6.the lack of sodium carbonate is taken, we find the amount of carbon dioxide:
n (CO2) = n (Na2CO3) = 0.1887 mol;
7.Calculate the mass of gas:
m (CO2) = n (CO2) * M (CO2);
M (CO2) = 12 + 32 = 44 g / mol;
m (CO2) = 0.1887 * 44 = 8.3 g.
Answer: 8.3 g.