To 100 ml of a solution of sulfuric acid with a mass fraction of 96% (p = 1.84 g / cm3) was added 300 ml of water.

To 100 ml of a solution of sulfuric acid with a mass fraction of 96% (p = 1.84 g / cm3) was added 300 ml of water. What is the mass fraction of the resulting solution in percent?

Let’s find the mass of the solution.

m = Vp.

m = 100 ml × 1.84 g / cm3 = 184 g.

W = m (substance): m (solution) × 100%, hence

m (substance) = (m (solution) × W): 100%.

m (substance) = (184 g × 96%): 100% = 176.64 g.

Find the mass of the solution after adding water.

m (solution) = m (water) 1 + m (solution) 1.

m (water) = 300 ml × 1 g / cm3 = 300 g.

m (solution) 2 = 300 g + 184 g = 484 g.

Let’s find the mass fraction of the substance in the resulting solution.

W = (176.64: 484) × 100% = 36.57%.

Answer: 36.57%.