To 150 grams of 8% NaCl solution, 50 g of water was added, what is the mass fraction of sodium chlorine in the new solution?

Let’s find the mass of sodium chloride:
m (NaCl) = m (NaCl) p.-pa1 * w1 (NaCl) / 100 = 150 * 8/100 = 12 (g).
Let’s find the mass of the resulting solution:
m (NaCl) p.-pa2 = m (NaCl) p.-pa1 + m (H2O) = 150 + 50 = 200 (g).
Let’s find the mass fraction of sodium chloride in the resulting solution:
w2 (NaCl) = (m (NaCl) / m (NaCl) p.-pa2) * 100 = (12/200) * 100 = 6 (%).
Answer: 6%.



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