To 234 g of a 5% sodium chloride solution was added 687 g of a 10% silver nitrate solution

| June 27, 2021 | education

To 234 g of a 5% sodium chloride solution was added 687 g of a 10% silver nitrate solution. Determine the mass of the sediment.

NaCl + AgNO3 = AgCl + NaNO3.
The precipitate is silver chloride.
1) The mass of the dissolved substance of sodium chloride is: 234 * 5/100 = 11.7 g.
2) Molar mass of sodium chloride: 23 + 35.5 = 58.5.
3) The amount of sodium chloride substance: 11.7 / 58.5 = 0.2 mol.
4) The mass of the solute of silver nitrate: 687 * 10/100 = 68.7 g.
5) The amount of silver nitrate substance: 68.7 / 170 = 0.4 mol.
Lack of sodium chloride. The calculation is carried out on it.
6) The molar mass of the sediment is: 143.
7) The amount of sediment substance is equal to: 0.2 mol.
7) We calculate the mass of the sediment: 143 * 0.2 = 28.6 g – the answer.



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