To 250 g of a 10% glucose solution, 150 ml of water was added. What is the mass fraction

To 250 g of a 10% glucose solution, 150 ml of water was added. What is the mass fraction of glucose in the solution obtained after dilution?

Given:
m p-pa1 (C6H12O6) = 250 g
w1 (C6H12O6) = 10% = 0.1
m (H2O) = 150 ml = 150 g
To find:
w2 (C6H12O6)
Decision:
m p-pa2 (C6H12O6) = 250 g + 150 g = 400 g
Since m in-VA1 (C6H12O6) = m in-VA2 (C6H12O6), then
250 * 0.1 = 400x
x = 0.0625
w2 (C6H12O6) in% = 0.0625 * 100% = 6.25%
Answer: 6.25%