To 30 grams of 25% aluminum chloride added alkali naoh find the mass of the precipitate.

univerkov | November 30, 2020 | education

AlCl3 + 3NaOH = Al (OH) 3 + 3NaCl
find the mass of dissolved aluminum chloride
m (AlCl) = 30 * 0.25 = 7.5
find the amount of aluminum chloride substance
n (AlCl) = 7.5 / 133.5 = 0.06 mol
the amount of substance aluminum chloride and aluminum hydroxide is equal to
m (Al (OH) 3) = 0.06 * 78 = 4.68g

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