To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen
To 300 liters of air was added 60 liters of nitrogen. Calculate the masses of oxygen and nitrogen that can be obtained from this mixture?
1) The air contains 78 percent nitrogen. This means that 60 liters contains 46.8 liters of nitrogen.
2) The volume of nitrogen after addition is: 46.8 + 60 = 106.8 liters.
3) The amount of nitrogen substance is equal to: 106.8 / 22.4 = 4.8 mol.
4) Find the mass of nitrogen. To do this, we multiply the molar mass by the amount of substance: 4.8 * 28 = 134.4 g.
5) The air contains 21 percent nitrogen. This means that 60 liters contains 12.6 liters of oxygen.
6) The amount of oxygen is equal to: 12.6 / 22.4 = 0.6 mol.
7) The mass of oxygen is: 0.6 * 12.6 = 7.56 g.
Answer: the mass of nitrogen is 134.4 g, the mass of oxygen is 7.56 g.