To 340 g of a solution with a mass fraction of magnesium nitrate of 4 percent, an excess of phosphoric acid solution

univerkov | November 20, 2020 | education

To 340 g of a solution with a mass fraction of magnesium nitrate of 4 percent, an excess of phosphoric acid solution was added. Calculate the mass of the precipitate formed.

Let’s write the reaction equation: Mg (NO3) 2 + 2H3PO4 = Mg3 (PO4) 2 + 6HNO3.
We calculate the mass of magnesium nitrate: 0.04 * 340 = 13.6 (g).
Let’s calculate the amount of magnesium nitrate substance: 13.6 / 148 = 0.09 (mol).
The amount of magnesium nitrate substance will be equal to the amount of the precipitate substance.
Find the mass of the sediment: 0.09 * 262 = 23.58 (g).

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