To 340 g of a solution with a mass fraction of silver nitrate 5%. Sodium bromide solution was added.

| February 27, 2021 | education

To 340 g of a solution with a mass fraction of silver nitrate 5%. Sodium bromide solution was added. Calculate the mass of the precipitate.

AgNO3 + NaBr = AgBr + NaNO3.
According to the solubility table, we determine that sodium bromide will be an insoluble substance in this reaction. Its mass must be determined.
-According to the data available in the task, we can calculate the mass of the solute in the silver nitrate solution:
5 = (x / 340) * 100.
x = 17g.
– We calculate the amount of silver nitrate substance. To do this, divide the mass of silver nitrate by its molar mass:
17/170 = 0.1 mol.
-According to the reaction equation, we see that for one mole of silver nitrate there is one mole of silver bromide. This means that the amount of silver bromide substance is 0.1 mol.
-Mass of silver bromide: 0.1 * 188 = 18.8 g – answer.



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