To 49 g of sulfuric acid solution was added barium chloride in a stoichiometric ratio.

To 49 g of sulfuric acid solution was added barium chloride in a stoichiometric ratio. As a result of the reaction, 23.3 g of salt was formed. In and calculate the mass fraction of sulfuric acid in the initial solution.

Barium chloride salt reacts with sulfuric acid. This results in the formation of water-insoluble barium sulfate, which precipitates. This reaction is described by the following chemical equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equivalent molar amounts. This produces the same amount of insoluble barium sulfate.

Determine the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol;

N BaSO4 = 23.3 / 233 = 0.1 mol;

Find the weight of the same amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.1 x 98 = 9.8 grams;

The acid concentration will be 9.8 / 49 = 0.2 = 20%;