To 500 g of a 10% solution of copper (II) sulfate 1. To 500 g of a 10% solution of copper (II)

To 500 g of a 10% solution of copper (II) sulfate 1. To 500 g of a 10% solution of copper (II) sulfate was added 10 g of anhydrous copper (II) sulfate. Determine the mass fraction of salt in the resulting solution.

Given:
m1 solution (CuSO4) = 500 g
ω1 (CuSO4) = 10%
m2 (CuSO4) = 10 g

Find:
ω3 (CuSO4) -?

1) m1 (CuSO4) = ω1 * m1 solution / 100% = 10% * 500/100% = 50 g;
2) m3 (CuSO4) = m1 + m2 = 50 + 10 = 60 g;
3) m3 solution (CuSO4) = m1 solution + m2 = 500 + 10 = 510 g;
4) ω3 (CuSO4) = m3 * 100% / m3 solution = 60 * 100% / 510 = 12%.

Answer: The mass fraction of CuSO4 is 12%.