To 53 g of sodium carbonate was added 73 g of hydrochloric acid. Evolved gas volume …

Given:
m (Na2CO3) = 53 g
m (HCl) = 73 g

To find:
V (gas) -?

Decision:
1) Na2CO3 + 2HCl => 2NaCl + CO2 ↑ + H2O;
2) n (Na2CO3) = m (Na2CO3) / M (Na2CO3) = 53/106 = 0.5 mol;
3) n (HCl) = m (HCl) / M (HCl) = 73 / 36.5 = 2 mol;
4) n (CO2) = n (Na2CO3) = 0.5 mol;
5) V (CO2) = n (CO2) * Vm = 0.5 * 22.4 = 11.2 liters.



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