To 60 g of a 12% sodium carbonate solution was added 24 g of a 15% orthophosphoric acid solution.

| August 8, 2021 | education

To 60 g of a 12% sodium carbonate solution was added 24 g of a 15% orthophosphoric acid solution. Find the volume of evolved gas.

The equation of the ongoing reaction: 3Na2CO3 + 2H3PO4 = 2Na3PO4 + 3H2O + 3CO2.
1) Mass of sodium carbonate substance: 60 * 12/100 = 7.2 g.
2) The amount of sodium carbonate substance: 7.2 / 106 = 0.07 mol.
3) The mass of the substance of orthophosphoric acid: 24 * 15/100 = 3.6 g.
4) Amount of acid substance: 3.6 / 98 = 0.04 mol.
The acid is in short supply. Further calculation is carried out on it.
5) According to the reaction equation, there are 3 moles of carbon dioxide per 2 mol of phosphoric acid. Thus, the amount of carbon dioxide substance is: 0.08 * 3 = 0.027 mol.
6) The volume of released gas: 0.027 * 22.4 = 0.6 liters – the answer.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.