To 7 l of 60% acid solution, 3 l of water was added. Determine the percentage of acid in the resulting solution.

1) 7 • 0.6 = 4.2 (l) -acids in 7 liters of solution
2) 7 + 3 = 10 (l) -solution became after adding water.
3) Let’s solve using proportions:
10x = 100 * 4.2
10x = 420
x = 42%
Answer: 42% acid content in the resulting solution.



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