To 700 g of an aqueous solution of ethanol with a mass fraction of 20% was added 240 ml of C2H5OH

| September 1, 2021 | education

To 700 g of an aqueous solution of ethanol with a mass fraction of 20% was added 240 ml of C2H5OH (p = 0.80 g / ml). Calculate the mass of alcohol in the resulting solution

1. Let’s calculate the mass of ethanol in the initial solution:

min (C2H5OH) = win (C2H5OH) * min (solution) = 0.2 * 700 = 140 g;

2.Calculate the mass of added alcohol:

madd (C2H5OH) = Vadd (C2H5OH) * ρ = 240 * 0.8 = 192 g;

3. find the mass of the resulting solution:

mpol (solution) = mout (solution) + madd (C2H5OH) = 700 + 192 = 892 g;

4.determine the total mass of ethanol:

mtot (C2H5OH) = minx (C2H5OH) + madd (C2H5OH) = 140 + 192 = 332 g;

5.Set the mass fraction of alcohol in the resulting solution:

wpol (C2H5OH) = mtot (C2H5OH): mpol (solution) = 332: 892 = 0.3722 or 37.22%.

Answer: 37.22%.



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