To 80 g of an 8% sucrose solution, 60 g of sucrose was added and 20 g of water was added.

To 80 g of an 8% sucrose solution, 60 g of sucrose was added and 20 g of water was added. what was the mass fraction of sucrose after that?

1. Let’s calculate the mass of sucrose in the initial solution:

min (C12H22O11) = win (C12H22O11) * min (solution) = 0.08 * 80 = 6.4 g;

2.Calculate the mass of sucrose after adding a portion:

mpol (C12H22O11) = minx (C12H22O11) + madd (C12H22O11) = 6.4 + 60 = 66.4 g;

3. find the mass of the resulting solution:

mpol (solution) = mout (solution) + madd (C12H22O11) + mdb (H2O) = 80 + 60 + 20 = 160 g;

4.determine the resulting mass fraction of sucrose:

wpol (C12H22O11) = mpol (C12H22O11): mpol (solution) = 66.4: 160 = 0.415 or 41.5%.

Answer: 41.5%.