To a 20% saline solution was added water equal to 25% of the amount of water in the solution.

To a 20% saline solution was added water equal to 25% of the amount of water in the solution. Find the salt concentration in the resulting solution.

To solve the problem, you first need to determine the percentage of water in the solution.

Since we know that the solution contains 20% salt, and the entire solution is 100%, we get:

100% – 20% = 80%. (Water in the starting solution.)

We find how much water was added to the solution.

Multiply 80% by 25%.

We get:

80% * 25% = 0.8 * 0.25 = 0.2 or 20% more water was added.

In this case, the total weight of the solution was:

100% + 20% = 120%.

Find the salt concentration in the new solution.

20% / 120% * 100% = 16.67%.