To a conductor, the resistance of which is 250 Ohm, a conductor with a resistance of 50 Ohm
| February 16, 2021 | education
To a conductor, the resistance of which is 250 Ohm, a conductor with a resistance of 50 Ohm was connected in parallel. Prove that their total resistance will be less than 50 ohms.
Task data: R1 (resistance of the original conductor) = 250 Ohm; R2 (resistance of the additionally connected conductor) = 50 Ohm; parallel connection.
To prove that the resistance of the conductors in question will be less than 50 Ohms, we use the formula to determine the resistance of parallel-connected resistors: R = R1 * R2 / (R1 + R2).
Calculation: R = 250 * 50 / (250 + 50) = 12,500 / 300 = 41.67 ohms.
Answer: The resistance of the resulting compound is 41.67 ohms.
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