To a solution containing 10.6 g of sodium carbonate was added 19.6 g of sulfuric acid, calculate the volume of gas evolved.

na2co3 + h2so4 = na2so4 + h2o + co2
find the amount of sodium carbonate and sulfuric acid
n (na2co3) = 10.6 / 106 = 0.1mol
n (h2so4) = 19.6 / 98 = 0.2 mol
sulfuric acid is taken in excess, which means we count by sodium carbonate
n (na2co3) = n (co2) = 0.1mol
v (co2) = 0.1 * 22.4 = 2.24 l



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