To a solution containing 10 g of hydrochloric acid was added 5 g of zinc.

To a solution containing 10 g of hydrochloric acid was added 5 g of zinc. determine the mass of the salt obtained. how much hydrogen was released?

The reaction proceeds according to the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s calculate the chemical amount of hydrogen chloride. For this purpose, we divide its weight by the mass of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 10 / 36.5 = 0.274 mol;

Let’s determine the molar amount of zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 5/65 = 0.077 mol;

With this amount of zinc, 0.077 x 2 = 0.154 mol of acid will react. This will receive 0.077 mol of hydrogen and 0.077 mol of zinc chloride. Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.077 x 22.4 = 1.7248 liters;

Let’s find the mass of zinc chloride.

M ZnCl2 = 65 + 35.5 x 2 = 136 grams / mol;

m ZnCl2 = 0.077 x 136 = 10.472 grams;