To a solution containing 10 g of sodium hydroxide, 30 g of a 30% solution of sulfuric acid was added. What salt and how much was formed?
When sodium hydroxide and sulfuric acid react, sodium sulfate and water are formed.
Reaction equation: 2NaOH + H2SO4 = Na2SO4 + 2H2O.
1) Molar mass of sodium hydroxide: 23 + 1 + 16 = 40.
2) The amount of sodium hydroxide substance: 10/40 = 0.25 mol.
3) The mass of the dissolved substance of sulfuric acid: 30 * 30/100 = 9g.
4) Molar mass of sulfuric acid: 1 * 2 + 32 + 4 * 16 = 98.
5) Amount of sulfuric acid substance: 9/98 = 0.09 mol.
Lack of sulfuric acid. The calculation is carried out on it.
6) According to the reaction equation, the amount of sodium sulfate substance is 0.09 mol.
7) Mass of sodium sulfate: 0.09 * 142 = 12.78 g – answer.
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