To a solution containing 30 g of acetic acid was added a solution containing 5.3 g of sodium carbonate.

To a solution containing 30 g of acetic acid was added a solution containing 5.3 g of sodium carbonate. Calculate the amount of carbon dioxide released during this process.

Let’s implement the solution:

In accordance with the condition of the problem, we compose the equation of the process:

2СН3СООН + Na2CO3 = 2CH3COONa + CO2 + H2O – ion exchange, carbon dioxide is released;

Calculations by formulas:
M (CH3COOH) = 60 g / mol;

M (Na2CO3) = 105.8 g / mol.

Let’s determine the amount of starting materials:
Y (CH3COOH) = m / M = 30/60 = 0.5 mol (substance in excess);

Y (Na2CO3) = m / M = 5.3 / 105.8 = 0.05 mol (deficient substance);

Y (CO2) = 0.05 mol since the amount of these substances is 1 mol.

Calculations are made for the substance in deficiency.

Find the volume of the product:
V (CO2) = 0.05 * 22.4 = 1.12 L

Answer: the volume of carbon dioxide was 1.12 liters