To a solution containing 35 g of nitric acid was added 14 g of calcium oxide. Determine the mass of the salt formed.

1. Let’s execute the solution:
2HNO3 + CaO = Ca (NO3) 2 + H2O – ion exchange, calcium nitrate is obtained;
2. Calculations:
M (HNO3) = 63 g / mol.
M (CaO) = 56 g / mol.
M Ca (NO3) 2 = 164 g / mol.
3. Determine Y (amount) of starting substances:
Y (HNO3) = m / M = 35/63 = 0.5 mol (substance in excess).
Y (CaO) = m / M = 14/56 = 0.25 mol (deficient substance).
Y Ca (NO3) 2 = 0.25 mol since the amount of substances according to the equation is 1 mol.
4. Salt content:
m Ca (NO3) 2 = Y * M = 0.25 * 164 = 41 g.
Answer: The mass of calcium nitrate is 41 g.