To a solution containing 37.25 g of potassium chloride was added a solution containing 0.2 mol

To a solution containing 37.25 g of potassium chloride was added a solution containing 0.2 mol of silver nitrate. What is the mass of the resulting sediment?

1. KCl + AgNO3 = AgCl ↓ + KNO3;

2. M (KCl) = 39 + 35.5 = 74.5 g / mol;

3.n (KCl) = m (KCl): M (KNO3);

n (KCl) = 37.25: 74.5 = 0.5 mol;

4.n (AgNO3) = 0.2 according to the condition of the problem, which is less than n (KCl), therefore we solve according to the drawback:

n (AgCl) = 0.2 mol;

5. M (AgCl) = 108 + 35.5 = 143.5 g / mol;

6. m (AgCl) = n (AgCl) * M (AgCl);

m (AgCl) = 0.2 * 143.5 = 28.7 g.

Answer: 28.7 g.