To a solution containing 4.9 g of sulfuric acid, a solution containing 11 g of barium chloride was added

To a solution containing 4.9 g of sulfuric acid, a solution containing 11 g of barium chloride was added. Calculate the mass of salt that is formed.

Given:
m (H2SO4) = 4.9 g
m (BaCl2) = 11 g

To find:
m (salt) -?

Decision:
1) H2SO4 + BaCl2 => 2HCl + BaSO4 ↓;
2) n (H2SO4) = m (H2SO4) / Mr (H2SO4) = 4.9 / 98 = 0.05 mol;
3) n (BaCl2) = m (BaCl2) / Mr (BaCl2) = 11/208 = 0.053 mol;
4) n (BaSO4) = n (H2SO4) = 0.05 mol;
5) m (BaSO4) = n (BaSO4) * Mr (BaSO4) = 0.05 * 233 = 11.65 g.

Answer: The mass of BaSO4 is 11.65 g.