To a solution containing 53 g of sodium carbonate was added 70 g of hydrochloric acid. What gas is generated?
To a solution containing 53 g of sodium carbonate was added 70 g of hydrochloric acid. What gas is generated? Calculate its volume?
The equation of the ongoing reaction: Na2CO3 + 2HCl = 2NaCl + H2O + CO2.
During the reaction, carbon dioxide is formed.
1) Find the molar mass of sodium carbonate: 2 * 23 + 12 + 48 = 108.
2) Find the amount of sodium carbonate substance. To do this, divide its mass by molar mass: 53/108 = 0.49 mol.
3) Find the molar mass of hydrochloric acid: 1 + 35.5 = 36.5.
4) Find the amount of hydrochloric acid substance: 70 / 36.5 = 1.9 mol.
Lack of sodium carbonate. We calculate on it.
5) According to the reaction equation, there is one mole of carbon dioxide per mole of sodium carbonate. hence, the amount of gas substance is equal to 0.49 mol.
6) Gas volume: 0.49 * 22.4 = 10.976 l – answer.