To a solution containing 54 g of acetic acid was added 6 g of magnesium. Calculate the amount

To a solution containing 54 g of acetic acid was added 6 g of magnesium. Calculate the amount of hydrogen released during this process.

Metallic magnesium dissolves in acetic acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2CH3COOH = Mg (CH3COO) 2 + H2 ↑;

Find the chemical amount of acetic acid.

For this purpose, we divide its weight by the weight of 1 mole of acid.

M CH3COOH = 12 x 2 + 16 x 2 + 4 = 60 grams / mol;

N CH3COOH = 54/60 = 0.9 mol;

Half the amount of hydrogen will be synthesized and half the amount of metallic magnesium will also be spent. That is, no more than 0.45 mol.

Determine the amount of magnesium available.

M Mg = 24 grams / mol;

N Mg = 6/24 = 0.25 mol;

Therefore, the acid is taken in excess.

Let’s calculate the volume of hydrogen.

To do this, multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.25 x 22.4 = 5.6 liters;