To a solution containing copper chloride, added 100 g of sodium hydroxide, find the mass of the formed copper hydroxide?

Given:
m (CuCl2) = 100 g

To find:
m (Cu (OH) 2) -?

1) CuCl2 + 2NaOH => Cu (OH) 2 ↓ + 2NaCl;
2) n (CuCl2) = m / M = 100/135 = 0.74 mol;
3) n (Cu (OH) 2) = n (CuCl2) = 0.74 mol;
4) m (Cu (OH) 2) = n * M = 0.74 * 98 = 72.5 g.

Answer: The mass of Cu (OH) 2 is 72.5 g.



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