To a solution containing sulfuric acid weighing 19.6 g, added a solution containing barium

| February 27, 2021 | education

To a solution containing sulfuric acid weighing 19.6 g, added a solution containing barium nitrate weighing 26.1 g, calculate the amount and weight of the resulting precipitate.

m (H2SO4) = 19.6 g.
m (Ba (NO3) 2) = 26.1.
Determine the mass and amount of the substance of the resulting sediment.
We write down the reaction equation.
H2SO4 + Ba (NO3) 2 = BaSO4 + 2HNO3.
Find the amount of sulfuric acid and barium nitrate.
n = m / M.
M (H2SO4) = 98 g / mol.
M (Ba (NO3) 2) = 261 g / mol.
n (H2SO4) = 19.6 / 98 = 0.2 mol.
n (Ba (NO3) 2) = 26.1 / 261 = 0.1 mol.
Sulfuric acid is in excess, which means we count on barium nitrate.
0.1 mol Ba (NO3) 2 – x mol BaSO4.
1 mol Ba (NO3) 2 – 1 mol BaSO4.
X = 0.1 * 1: 1 = 0.1 mol BaSO4.
Find the mass of barium sulfate.
m = n * M = 0.1 mol * 261 g / mol = 26.1 g.
Answer: the mass of barium sulfate is 26.1; the amount of substance is 0.1 mol.



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