To a solution of sulfate acid weighing 98 g with a mass fraction of 10% was added 10 g of sodium hydroxide.

To a solution of sulfate acid weighing 98 g with a mass fraction of 10% was added 10 g of sodium hydroxide. Calculate the mass of salt that has formed.

1. Let’s write down the possible reaction equations:

H2SO4 + 2NaOH = Na2SO4 + 2H2O;

H2SO4 + NaOH = NaHSO4 + H2O;

2. find the mass of sulfuric acid:

m (H2SO4) = w (H2SO4) * m (solution);

m (H2SO4) = 0.1 * 98 = 9.8 g;

3.Calculate the chemical quantities of reactants:

n (H2SO4) = m (H2SO4): M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

n (H2SO4) = 9.8: 98 = 0.1 mol;

n (NaOH) = m (NaOH): M (NaOH);

M (NaOH) = 23 + 16 + 1 = 40 g / mol;

n (NaOH) = 10: 40 = 0.25 mol;

4.the lack of hydroxide, therefore, an acidic salt is formed – sodium hydrogen sulfate, we will find its amount and mass:

n (NaHSO4) = n (NaOH) = 0.25 mol;

m (NaHSO4) = n (NaHSO4) * M (NaHSO4);

M (NaHSO4) = 23 + 1 + 32 + 4 * 16 = 120 g / mol;

m (NaHSO4) = 0.25 * 120 = 30 g.

Answer: 30 g.