To a solution weighing 15 g with a mass fraction of hydrogen chloride 10% was added a solution
To a solution weighing 15 g with a mass fraction of hydrogen chloride 10% was added a solution with a mass of 10 g mass fraction of hydrogen chloride 28%. Determine the mass fraction of HCI in the resulting solution.
Given:
m1 solution (HCl) = 15 g
ω1 (HCl) = 10%
m2 solution (HCl) = 10 g
ω2 (HCl) = 28%
To find:
ω3 (HCl) -?
Decision:
1) Find the mass of dry matter HCl in the first and second solutions:
m1 (HCl) = ω1 (HCl) * m1 solution (HCl) / 100% = 10% * 15/100% = 1.5 g;
m2 (HCl) = ω2 (HCl) * m2 solution (HCl) / 100% = 28% * 10/100% = 2.8 g;
2) Find the mass of the HCl substance in the resulting solution:
m3 (HCl) = m1 (HCl) + m2 (HCl) = 1.5 + 2.8 = 4.3 g;
3) Find the mass of the resulting HCl solution:
m3 solution (HCl) = m1 solution (HCl) + m2 solution (HCl) = 15 + 10 = 25 g;
4) Find the mass fraction of HCl in the resulting solution:
ω3 (HCl) = m3 (HCl) * 100% / m3 solution (HCl) = 4.3 * 100% / 25 = 17.2%.
Answer: Mass fraction of HCl in the resulting solution was 17.2%.