To a solution weighing 200 g with a mass fraction of glucose 10% was added 50 cm3 of water (water density 1 g / cm3).

To a solution weighing 200 g with a mass fraction of glucose 10% was added 50 cm3 of water (water density 1 g / cm3). Determine the mass fraction of glucose in the resulting solution

1.Let’s find the mass of glucose in the solution.

W = m (substance): m (solution) × 100%,

hence m (substance) = (m (solution) × w): 100%.

m (substance) = (200 g x 10%): 100% = 20 g.

Or:

200 g – 100%,

x- 10%,

x = (200 g × 10%): 100 = 20 g.

2. Let’s find the mass of water.

V = m: ρ,

m = V ρ.

m = 50 cm3 × 1 g / cm3 = 50 g.

3.m (solution) = m (water) + = m (substance).

m (solution) = 50 g + 20 g = 70 g.

4.Let’s find the mass fraction of a substance by the formula:

W = m (substance): m (solution) × 100%,

W = (20g: 70g) × 100% = 28.57%.

Answer: 28.57%.